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AQA A-Level Physics: Gravitational Field Lines and Gravitational Field Strength — mark scheme explained

Machine-verifiedchecked against the AQA A-Level Physics specificationlast verified 2 July 2026

The short answer

In this section, we will explore the representation of gravitational fields using field lines and delve into the concept of gravitational field strength ( g ). We will also derive and understand the formula for g in a radial field.

The question

Calculate the gravitational field strength at a distance of 4,000 km from the center of a planet with a mass of 7 × 10 23 kg. [Paraphrased for study — not reproduced from any exam paper.]

Mark scheme, decoded

What each mark is really for — in plain English — and the wording trap that loses it.

  • S1

    Identify the given values: M = 7 × 10 23 kg, r = 4,000 km = 4,000,000 m, and G = 6.674 × 10 -11 N·m 2 /kg 2 .

  • S2

    Use the formula for gravitational field strength in a radial field: g = GM r 2

  • S3

    Substitute the values into the formula: g = (6.674 × 10 -11 ) (7 × 10 23 ) (4,000,000) 2

  • S4

    Calculate the numerator: (6.674 × 10 -11 ) (7 × 10 23 ) = 4.6718 × 10 13 N·m 2 /kg

  • S5

    Calculate the denominator: (4,000,000) 2 = 1.6 × 10 13 m 2

  • S6

    Divide the numerator by the denominator: g ≈ 4.6718 × 10 13 1.6 × 10 13

  • S7

    Simplify the result: g ≈ 2.92 m/s 2

Model answer

Worked through, with each step tagged to the mark it earns.

  1. S1

    Identify the given values: M = 7 × 10 23 kg, r = 4,000 km = 4,000,000 m, and G = 6.674 × 10 -11 N·m 2 /kg 2 .

  2. S2

    Use the formula for gravitational field strength in a radial field: g = GM r 2

  3. S3

    Substitute the values into the formula: g = (6.674 × 10 -11 ) (7 × 10 23 ) (4,000,000) 2

  4. S4

    Calculate the numerator: (6.674 × 10 -11 ) (7 × 10 23 ) = 4.6718 × 10 13 N·m 2 /kg

  5. S5

    Calculate the denominator: (4,000,000) 2 = 1.6 × 10 13 m 2

  6. S6

    Divide the numerator by the denominator: g ≈ 4.6718 × 10 13 1.6 × 10 13

  7. S7

    Simplify the result: g ≈ 2.92 m/s 2

  8. Final answer: 2.92 m/s 2

Common mistakes

  • Confusing the units of gravitational field strength — Always remember that the unit of gravitational field strength is newtons per kilogram (N/kg) or meters per second squared (m/s 2 ).
  • Using the wrong formula for gravitational field strength — Ensure you are using the correct formula: g = GM r 2 . The gravitational force formula is F = Gm 1 m 2 r 2 .
  • Forgetting to convert distances from kilometers to meters — Always ensure that all distances are in meters before substituting them into the formula. For example, 10,000 km = 10,000,000 m.
  • Misinterpreting the direction of gravitational field lines — Gravitational field lines always point towards the mass, indicating the attractive nature of gravity. This is different from electric field lines, which can point away from positive charges.
  • Using the wrong value for the gravitational constant — Always use the correct value of the gravitational constant: G = 6.674 × 10 -11 N·m 2 /kg 2 . Double-check that you have included it in your calculations.
  • Confusing the radius of a planet with the distance from its center — When calculating gravitational field strength at a point outside the surface of a planet, add the altitude to the radius of the planet to get the total distance r from the center. For example, if you are 1,000 km above the surface of a planet with a radius of 5,000 km, r = 6,000 km.

Where the marks go

  • Full worked solution (all marking points)6 marks

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