A-Level · Physics · AQA · Mark scheme decoded

AQA A-Level Physics: Displacement, Speed, Velocity, and Acceleration — mark scheme explained

Machine-verifiedchecked against the AQA A-Level Physics specificationlast verified 2 July 2026

The short answer

In this section, we will explore the fundamental concepts of displacement, speed, velocity, and acceleration. These concepts are crucial for understanding motion in a straight line and form the basis for more advanced topics in mechanics.

The question

A car accelerates uniformly from rest to a speed of 20 m/s in 5 seconds. Calculate the acceleration and the distance traveled during this time. [Paraphrased for study — not reproduced from any exam paper.]

Mark scheme, decoded

What each mark is really for — in plain English — and the wording trap that loses it.

  • S1

    1. Identify the given values: initial velocity (u) = 0 m/s, final velocity (v) = 20 m/s, time (t) = 5 s.

  • S2

    2. Use the formula for acceleration: a = (v - u) / t

  • S3

    3. Substitute the values: a = (20 - 0) / 5 = 4 m/s 2

  • S4

    4. Use the formula for displacement: s = ut + (1/2)at 2

  • S5

    5. Substitute the values: s = 0 × 5 + (1/2) × 4 × 5 2 = 50 m

Model answer

Worked through, with each step tagged to the mark it earns.

  1. S1

    1. Identify the given values: initial velocity (u) = 0 m/s, final velocity (v) = 20 m/s, time (t) = 5 s.

  2. S2

    2. Use the formula for acceleration: a = (v - u) / t

  3. S3

    3. Substitute the values: a = (20 - 0) / 5 = 4 m/s 2

  4. S4

    4. Use the formula for displacement: s = ut + (1/2)at 2

  5. S5

    5. Substitute the values: s = 0 × 5 + (1/2) × 4 × 5 2 = 50 m

  6. Final answer: The acceleration is 4 m/s 2 and the distance traveled is 50 m.

Common mistakes

  • Confusing displacement with distance — Always check if the question asks for distance or displacement. Displacement can be positive, negative, or zero, depending on the direction of movement relative to a reference point.
  • Using average velocity instead of instantaneous velocity — Read the question carefully to determine if it asks for average or instantaneous velocity. Instantaneous velocity is the velocity at a specific moment in time, while average velocity is over an interval.
  • Forgetting to include units in calculations — Always write down the units for each quantity used in your calculations and ensure that the final answer has the correct units. For example, velocity should be in m/s, acceleration in m/s 2 , and displacement in meters.
  • Incorrectly interpreting the area under a velocity-time graph — Remember that the area under a velocity-time graph represents the displacement. The gradient (slope) of the graph gives the acceleration.
  • Using the wrong formula for uniform acceleration — Memorize and understand the four main equations for uniform acceleration: v = u + at, s = (u + v)t / 2, s = ut + (1/2)at 2 , and v 2 = u 2 + 2as. Choose the appropriate equation based on the given information in the question.
  • Neglecting the direction of acceleration — Always consider the direction of acceleration. For example, in free fall, the acceleration due to gravity (g) acts downwards and is therefore negative when using upward as the positive direction.
  • Incorrectly identifying random and systematic errors in practical experiments — Understand that random errors can be reduced by taking multiple measurements and calculating an average, while systematic errors require calibration of equipment or a consistent method. Identify potential sources of error in the experiment and suggest specific ways to minimize them.

Where the marks go

  • Full worked solution (all marking points)6 marks

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